20232023.03123456789101112DAACDBCBDCAD13.;14.;15;16.17ana3a8=4a2bnanbn7xx=2Cn=,Tn{cn}nana1,18adanan=bn=n=<<1bn=0n=<2bn=1n=<<3bn=2bn70+0+1+1+1+2+2=7.cn==().18122022.ABAB10060106[010)[1020)[2030)[3040)[4050)[502860]ABB[010)2[1020)3[2030)5[3040)15[4050)40[5060]35A100A30B[020)221[010)ABAAABmnBabcmnmambmcnanbncabacbcmambmcnanbncPA38ABBB19ABCDA1B1C1D1AB2FDD1EBB1GA1B1C1D1GGF//AECG.C1EAEC.CC1HFHF1AB1H.F,HD1D,C1CA1FHB1A1F//B1H48B1ECHA1F//ECA1FAECA1F//AECA1C1,C1F,A1F,HDC1F//AECA1FC1FFA1FC1//AECGGF//AECGA1FC1GA1C1yAABxADAA1zA0,0,0,C2,2,0,E2,0,1,C12,2,2,AECn(x,y,z)nAE,nAC2xz0xy0x1n(1,1,2)EC1(0,2,1)nEC1cos,==nEC1C1EAEC58230C1EAEC152012y2x2C:1ab0Ca2b2Ey2=2px(p>0)4()CE()lEABCMNOOAOB4xHxMHNH()a212b29y2x2C1129C3,0p2Ey24x()l0lykxmAx1,y1Bx2,y268ykxmy24xyk2x22km4xm2022212km44km16km160km122km42km24my1y2kx1mkx2mkx1x2kmx1x2m2mk2km24mOAOBxxyy41212k2km2kkm2k21lykx2xHx0,0xMHNHMHN0Mx3,y3Nx4,y4y3k24x212k2x12k236022222212k43k412k3605k12012k212k236xxxx343k24343k24yy340x3x0x4x0kx32x4x0kx42x3x00782x3x4x02x3x44x0024k27212k2x24x03k2403k24016x72003k249xH,0xMHN221alnxf(x)(aR)xf(x)g(x)=lnxlah(x)f(x)axlg(x)lnxx0,y0l------------------------------------------1l---------------------------------------2(0,0)y01x0el-------------------------------------31m(x)x2lnxe88m(x)0--------------------------------------------------------4ln2m(x)0,m(x),2ln2m(x)0,m(x),------52lf(x)a---------------------------------------------6k(x)ax2lnxa--------------------------7k(1)0x1k(x)----------------------------8k(x)k(x)0-----------------------------------------------9k(x)0,k(x)k(x)0,k(x)k(x)--------------1098kx0ux00k(x)--------------------11h(x)x1------------------------------------1222.4-4xOyClx+yxClClABABOx1cosysincosx1sinycos2sin212Cx1y21108xcos,ysinlC2cosl23.4-5fxxxm,(mR)m1f(x)2xfxx3mm1fxxxfx2x1x1x2fx2x4x4118fx2x1x13xfx2x1fx2x1x1x2fx2x0x1fx23,4x3,4xmx4x4xmx44m2x4x3,4x32x4m4,10128
理科数学答案解析
2023-11-22
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12页
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