内蒙古包头市2023-2024学年高三上学期期末考试理科综合物理答案

物理参考答案题号1415161718192021答案CBCDAACADBD22.（每空2分）（1）BF（2）1.8022(m1m2)(h4h2)f（3）(m1m2)gh320023.（1）（3分）49（2）B（2分）（3）AC（2分）（4）（2分）3924.（1）b到a（下到上也可以给分）..............................2分（2）22vv02ax...........................................2分v2al...............................................1分BlvBl2alI..........................................2分RRBIlmg.............................................2分BIlB2l22al.....................................3分mgmgR1{#{QQABCQKAogAAAgBAAQgCUwG4CkEQkBAAACoOxAAIsAAAiBFABAA=}#}125.（1）mgrmv2......................................2分20v06m/s...............................................1分（2）mv0(mmp)v1....................................1分11mv2(mm)v2mgL............................1分202p11v12m/s..............................................1分L2.4m...............................................1分（3）mPv1mpvPmQv2.................................1分111mv2mv2mv2................................1分2P12pP2Q2vP0.4m/sv21.6m/s.............................................1分mga15m/s2.......................................1分1m（2mmQ)g1mg2a11m/s..........................1分mQ木块与木板Q均作匀减速到共速v3v1a1t1v2a2t1...................................2分t10.1s................................................1分v31.5m/s.............................................1分木块与木板Q一起做匀减速直线运动到停止（2mmQ)g2a32m/s................................1分（mmQ)2{#{QQABCQKAogAAAgBAAQgCUwG4CkEQkBAAACoOxAAIsAAAiBFABAA=}#}0v3t20.75s........................................2分a3tt1t20.85s.........................................1分33.（1）ABD（选对1个得2分，选对2个得4分选对3个得5分，错选1个扣3分，最低得0分）（2）（ⅰ）pBpA1.6p0p0V01.6p0VB..........................................2分5VV...............................................2分B80（ⅱ）511V2VVV...................................2分A08080pV1.6pV000A.........................................2分T0TA11TT...............................................2分A5033.（1）正（2分）；100（3分）sin1sin37（2）（ⅰ）n1.2.........................2分sin2sin30c5vc..............................................2分n6RR11Rt.........................................2分vc5c15（ⅱ）sinC....................................2分n611hRcosCR...................................2分63{#{QQABCQKAogAAAgBAAQgCUwG4CkEQkBAAACoOxAAIsAAAiBFABAA=}#}{#{QQABCQKAogAAAgBAAQgCUwG4CkEQkBAAACoOxAAIsAAAiBFABAA=}#}